; ACL2 Arithmetic Rationals-with-axioms-PROVED book. ; Copyright (C) 1998 John R. Cowles, University of Wyoming ; This book is free software; you can redistribute it and/or modify ; it under the terms of the GNU General Public License as published by ; the Free Software Foundation; either version 2 of the License, or ; (at your option) any later version. ; This book is distributed in the hope that it will be useful, ; but WITHOUT ANY WARRANTY; without even the implied warranty of ; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the ; GNU General Public License for more details. ; You should have received a copy of the GNU General Public License ; along with this book; if not, write to the Free Software ; Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA. ; Written by: ; John Cowles ; Department of Computer Science ; University of Wyoming ; Laramie, WY 82071-3682 U.S.A. #| Summer 1997 Last modified 30 June 1998 Depends on the Arithmetic Inequalities book and the Arithmetic Nonnegative Integer Mod and Gcd book. This book proves all the axioms in the Arithmetic Rationals-with-axioms book To certify in Arithmetic Book directory: (certify-book "rationals-with-axioms-proved" 0 nil) |# #| This comment is copied from the Arithmetic Rationals-with-axioms book: ; ACL2 books on arithmetic ; Copyright (C) 1997 Computational Logic, Inc. ; This book is free software; you can redistribute it and/or modify ; it under the terms of the GNU General Public License as published by ; the Free Software Foundation; either version 2 of the License, or ; (at your option) any later version. ; This book is distributed in the hope that it will be useful, ; but WITHOUT ANY WARRANTY; without even the implied warranty of ; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the ; GNU General Public License for more details. ; You should have received a copy of the GNU General Public License ; along with this book; if not, write to the Free Software ; Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA. ; Written by: ; Matt Kaufmann, Bishop Brock, and John Cowles, with help from Art Flatau ; Computational Logic, Inc. ; 1717 West Sixth Street, Suite 290 ; Austin, TX 78703-4776 U.S.A. (in-package "ACL2") (include-book "inequalities") ; The following three axioms seemed crucial for some of Matt ; Kaufmann's work, both in non-standard analysis and in a termination ; and guard verification exercise for axioms.lisp. After these three ; axioms is an informal argument that justifies them. Perhaps some ; day, someone will translate this informal proof to an Acl2 proof. (defaxiom denominator-unary-minus (implies (rationalp x) (equal (denominator (- x)) (denominator x)))) (defaxiom numerator-goes-down-by-integer-division (implies (and (integerp x) (< 0 x) (rationalp r) (<= 0 r)) (<= (numerator (* (/ x) r)) (numerator r))) :rule-classes :linear) (defaxiom denominator-plus (implies (and (rationalp r) (integerp i)) (equal (denominator (+ r i)) (denominator r))) :rule-classes (:rewrite (:rewrite :corollary (implies (and (rationalp r) (integerp i)) (equal (denominator (+ i r)) (denominator r)))))) #| Here are proofs of the three axioms above, using heavily some standard facts about gcd. Basic Fact: If r = p/q where all are rational, p and q are integers, and q is positive, then if g = gcd(|p|,q), we have (numerator r) = p/g, (denominator r) = q/g. Proof of Basic Fact. Let n1 = p/g, d1 = q/g, n = (numerator r), d = (denominator r). Thus we have n1/d1 = n/d, and we know that n1 and d1 are relatively prime. Let d2 = gcd(d1,d). We will show d2 = d. Let us write d = k*d2 (all positive integers) where k and d1 are relatively prime. Now n1*d=n*d1, so since k divides d, k divides n*d1, and hence since k and d1 are relatively prime, therefore k divides n. But then since k divides both n and d, we have a contradiction of lowest terms. Therefore k=1, and hence d = d2 = gcd(d1,d). Thus we may write d1 = i*d for some positive integer i. Now n1*d=n*d1, so n1*d=n*i*d, and hence n1 = n*i. So i divides both n1 and d1, which implies i = 1, and hence we're done. Corollary: gcd(|(numerator r)|,(denominator r)) = 1 for all rationals r. Proof. Setting p = (numerator r) and q = (denominator r) above, we obtain p = p/gcd(|p|,q) and hence p = 0 or else gcd(|p|,q) = 1. But if p = 0 then (denominator r) = 1 and hence gcd(|p|,q) = 1 in that case too. Lemma about gcd (stated without proof). gcd(|i+k*j|,j) = gcd(i,j) for integers i,j,k. (defaxiom denominator-unary-minus (implies (rationalp x) (equal (denominator (- x)) (denominator x)))) Proof. Let x = p/q, where p and q are the numerator and denominator of x. Then -x = (-p)/q, so (denominator -x) = q/gcd(|-p|,q) = q/gcd(p,q) = q/1 = q. (defaxiom denominator-plus (implies (and (rationalp r) (integerp i)) (equal (denominator (+ r i)) (denominator r)))) Proof. (+ r i) = (/ (+ n (* i d)) d), where n and d are the numerator and denominator of r. Now we have (denominator (+ r i)) = d/gcd(|+ n (* i d)|,d) by the Basic Fact. But using the lemma about gcd stated above, we have gcd(|+ n (* i d)|,d) = gcd(|n|,d) = 1, and hence we're done. (defaxiom numerator-goes-down-by-integer-division (implies (and (integerp x) (< 0 x) (rationalp r) (<= 0 r)) (<= (numerator (* (/ x) r)) (numerator r))) :rule-classes :linear) Let r = n/d, where n and d are its numerator and denominator. Then (* (/ x) r) = n/(x*d), so by the Basic Fact, (numerator (* (/ x) r)) = n/gcd(|n|,(x*d)) <= n. |# ; Here are some axioms that Bishop wanted. (encapsulate () (local (defthm /-cancellation-on-right-temp (implies (and (equal z (* x (/ y))) (rationalp x) (rationalp y) (not (equal y 0))) (equal (* y z) x)))) (defthm numerator-minus (equal (numerator (- i)) (- (numerator i))) :hints (("Goal" :use ((:instance rational-implies2 (x i)) (:instance rational-implies2 (x (- i))) (:instance denominator-unary-minus (x i))) :in-theory (disable rational-implies2 denominator-unary-minus)))) ) (encapsulate () (local (defthm numerator-/x-positive-case (implies (and (integerp x) (< 0 x)) (equal (numerator (/ x)) 1)) :rule-classes nil :hints (("Goal" :use ((:instance rational-implies2 (x (/ x))) (:instance lowest-terms (n (numerator (/ x))) (r 1) (q x) (x (/ x)))) :in-theory (disable rational-implies2 *-r-denominator-r))))) (defthm numerator-/x (implies (and (integerp x) (not (equal x 0))) (equal (numerator (/ x)) (signum x))) :hints (("Goal" :use (numerator-/x-positive-case (:instance numerator-/x-positive-case (x (- x))))))) ) |# (in-package "ACL2") (include-book "inequalities") (local (include-book "mod-gcd")) (defthm Denominator-unary-minus (implies (rationalp x) (equal (denominator (- x)) (denominator x))) :hints (("Goal" :use (:instance Unique-rationalp (d (denominator x)) (n (- (numerator x))))))) (defthm Numerator-goes-down-by-integer-division (implies (and (integerp x) (< 0 x) (rationalp r)) (<= (abs (numerator (* (/ x) r))) (abs (numerator r)))) :rule-classes ((:linear :corollary (implies (and (integerp x) (< 0 x) (rationalp r) (>= r 0)) (<= (numerator (* (/ x) r)) (numerator r)))) (:linear :corollary (implies (and (integerp x) (< 0 x) (rationalp r) (<= r 0)) (<= (numerator r) (numerator (* (/ x) r)))))) :hints (("Goal" :use (:instance LEAST-numerator-denominator-<= (n (numerator r)) (d (* x (denominator r))))))) (defthm Denominator-plus (implies (and (rationalp r) (integerp i)) (equal (denominator (+ i r)) (denominator r))) :hints (("Goal" :use ((:instance Unique-rationalp (d (denominator r)) (n (+ (numerator r)(* i (denominator r))))) (:instance Nonneg-int-gcd-abs (x (numerator r)) (j i) (n (denominator r))))))) ; Here are some axioms that Bishop wanted. (defthm Numerator-minus (equal (numerator (- i)) (- (numerator i))) :hints (("Goal" :cases ((rationalp i))) ("Subgoal 1" :use (:instance Unique-rationalp (d (denominator i)) (n (- (numerator i))))))) (defthm Numerator-/x (implies (and (integerp x) (not (equal x 0))) (equal (numerator (/ x)) (signum x))) :hints (("Goal" :use (:instance Unique-rationalp (n (signum x)) (d (abs x))))))