It is often easy to determine Big O directly from code:
for ( i = 0; i < n; i++ )
for ( j = 0; j < n; j++ )
sum += a[i][j];
We all know this is O(n2); but what about:
for ( i = 0; i < n; i++ )
for ( j = 0; j < = i; j++ )
sum += a[i][j];
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