Often one wants to build up a list incrementally; this is usually done using cons.
Note that for any x, (cons x '()) = (list x ) :
(cons 'a '()) = (a)
(cons '(a) '()) = ((a))
If lst is a list, then (cons x lst ) will make a new list with x as its first element, followed by the other elements of lst.
(cons 'a '(b c)) = (a b c)
(cons '(a) '(b c)) = ((a) b c)
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