Lecture Notes on 14 Oct 2011

// reversing an array in place
for (int i = 0; i < a.length / 2  ; i++)
{
  int tmp = a[i];
  a[i] = a[a.length - 1 - i];
  a[a.length - 1 - i] = tmp;
}

// find max in an array
int max = a[0];
for (int i = 0; i < a.length; i++)
{
  if (a[i] > max)
    max = a[i];
}