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Syntax-abstraction

Abs-scalar-literal

Abstract a scalar-literal to a scalar literal.

Signature
(abs-scalar-literal tree) → lit
Arguments: tree — Guard (abnf::treep tree).
Returns: lit — Type (literal-resultp lit).

Definitions and Theorems

Function: abs-scalar-literal

(defun abs-scalar-literal (tree)
  (declare (xargs :guard (abnf::treep tree)))
  (let ((__function__ 'abs-scalar-literal))
    (declare (ignorable __function__))
    (b* (((okf (abnf::tree-list-tuple2 sub))
          (abnf::check-tree-nonleaf-2 tree "scalar-literal"))
         ((okf num-tree)
          (abnf::check-tree-list-1 sub.1st))
         ((okf nat) (abs-numeral num-tree))
         ((okf scalar-tree)
          (abnf::check-tree-list-1 sub.2nd))
         ((okf &)
          (abnf::check-tree-schars scalar-tree "scalar")))
      (literal-scalar nat))))

Theorem: literal-resultp-of-abs-scalar-literal

(defthm literal-resultp-of-abs-scalar-literal
  (b* ((lit (abs-scalar-literal tree)))
    (literal-resultp lit))
  :rule-classes :rewrite)

Theorem: abs-scalar-literal-of-tree-fix-tree

(defthm abs-scalar-literal-of-tree-fix-tree
  (equal (abs-scalar-literal (abnf::tree-fix tree))
         (abs-scalar-literal tree)))

Theorem: abs-scalar-literal-tree-equiv-congruence-on-tree

(defthm abs-scalar-literal-tree-equiv-congruence-on-tree
  (implies (abnf::tree-equiv tree tree-equiv)
           (equal (abs-scalar-literal tree)
                  (abs-scalar-literal tree-equiv)))
  :rule-classes :congruence)