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Syntax-abstraction

Abs-?-finalizer

Abstract a [ finalizer ] to a finalizer-option.

Signature
(abs-?-finalizer tree) → final
Arguments: tree — Guard (abnf::treep tree).
Returns: final — Type (finalizer-option-resultp final).

Definitions and Theorems

Function: abs-?-finalizer

(defun abs-?-finalizer (tree)
  (declare (xargs :guard (abnf::treep tree)))
  (let ((__function__ 'abs-?-finalizer))
    (declare (ignorable __function__))
    (if (empty-optional-tree-p tree)
        nil
      (b* (((okf treess)
            (abnf::check-tree-nonleaf tree nil))
           ((when (endp treess)) nil)
           ((okf trees)
            (abnf::check-tree-list-list-1 treess))
           ((okf tree)
            (abnf::check-tree-list-1 trees)))
        (abs-finalizer tree)))))

Theorem: finalizer-option-resultp-of-abs-?-finalizer

(defthm finalizer-option-resultp-of-abs-?-finalizer
  (b* ((final (abs-?-finalizer tree)))
    (finalizer-option-resultp final))
  :rule-classes :rewrite)

Theorem: abs-?-finalizer-of-tree-fix-tree

(defthm abs-?-finalizer-of-tree-fix-tree
  (equal (abs-?-finalizer (abnf::tree-fix tree))
         (abs-?-finalizer tree)))

Theorem: abs-?-finalizer-tree-equiv-congruence-on-tree

(defthm abs-?-finalizer-tree-equiv-congruence-on-tree
  (implies (abnf::tree-equiv tree tree-equiv)
           (equal (abs-?-finalizer tree)
                  (abs-?-finalizer tree-equiv)))
  :rule-classes :congruence)